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Well, since Osprey has not provided a new nut to crack I have come up with my own:
I have three coins in my pocket that I, with huge precision, fit into the smallest equilateral triangle conceivable.
All three coins fit exactly, and sit as close next to each other as possible.
How great is the percentage of the triangle's area which is not covered by the coins?
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If I've understood it right (and haven't done any errors) the solution should go:
r = coin radius
Triangle area = r*r*(tan(30)*4 + 6)
coin area = 3*pi*r*r
no calculator to calculate the actual value
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Sorry, couldn't get any puzzle which might puzzle you
The answer is 16.something percent, if i have my calculations right.
Here's another one. (pretty simple)
I have 100 coins on the table. Out of them exactly 50 are heads up. You are blindfolded. You have to seperate the coins into two stacks with equal number of heads up. And you can't feel the coins. (assume a paper covers each side of the coin)
Death smiles at us all, All a man can do, is Smile Back
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I've done an error earlier on, tan(30) should be 1/tan(30) and if everything else is OK the answer should be 39%
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